Engineering FE Engineering Common Sem 1 Basic Electrical and Electronics Engineering Dec 2018 R16 Question Paper - Mumbai University | munotes
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Dec 2018 - CBSGS
Semester-end · Basic Electrical and Electronics Engineering
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Questions asked in this paper
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Q2 (A) Prove that the average power taken by a pure capacitor fed with a sinusoidal supply in a cycle is zero
- (B) Using mesh analysis find the mesh currents in the direction shown and also find the voltage across A and B terminals 10
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Q3 A) A single phase transformer has 1000 turns on the primary and 200 turns on the secondary. The no load current is 3A at a power factor of 0.2 lag and the secondary (10) current is 280A at a power factor of 0.8 lag. Neglect Ro and X2. Calculate component and loss component of no load current; (ii)Primary current (i11) Input power factor. Draw the phasor diagram showing all these currents 10 marks
- (B) Derive the formula for resonant frequency of the circuit with a pure capacitor in parallel with a coil having resistance and inductance. Find the expression for dynamic resistance of this parallel resonant circuit 10
- (B) A resistance and a capacitance connected in series across a 250V supply draws. 5A at 50 Hz. When frequency is increased to 60 Hz, it draws 5.8A. Find the values of R & C. Also find active power and power factor in both cases 10
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Q5 (A) Find the node voltages Vi, V2 and V3 and current through 0.5Q. 10 marks
- (B) Describe the basic principle of operation of a single phase transformer and derive the emf equation 10
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Q6 (A) Determine the value of R for maximum power transfer and find the value of 10 marks
- (B) The O.C and S.C test data are given below for a single phase, 5 kVA, 10
- O.C test from LV side: 200V 1.25A 150W
- S.C test from HV side: 175W Determine the following: (1) Draw the equivalent circuit of the transformer referred to LV side (ii) At what load or kVA the transformer is to be operated for maximum efficiency? (iit) Calculate the value of maximum efficiency. (iv) Regulation of the transformer at full load 0.8 power factor lag
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