BSc Sem II 2012 2014 2014 Phy Ll Question Paper - Mumbai University | munotes
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Questions asked in this paper
- ii) Figures to the right indicate ful} marks
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Q1 Answer the following: Three)
- a) A particle is Subjected to to perpendicular SHM’s x= Acoswt and Acos(wt — =) Find trajectory of the Particle,
- b) Explain the Concept of centre of mass of a System of particles, Define Simple Harmonic Motion. Show that a particle whose potential energy is % kx? where k is a constant SHM masses 2kp 3kg and 4kg are located at 4) and (3, 1, 2) Find the centre of Mass of this system
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Q2 Answer the following: ~(Any Three) the lenses & L2 of focal length f; and are placed Parallel to each other along the optic axis than derive an for focal length of a combination,
- b) Explain the term “deviation in case of lens”. Hence Prove that the deviation does not depend on the position of object, With a Suitable Tay diagram, spherical Abberation of lens, State the method of
- d) Describe how will you determine Refractive Index of Prism using
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Q3 Answer the following: Three) [1SMarks]
- a) Draw labelled-diagram of thé following:
- i) Laser cutter and li) A typical system
- b) Explain the following terms: i) Monochromaticity
- iii) Coherence
- iv) Intensity and Power
- c) Explain recording of the Hologram
- d) Calculate the numerical aperture of a step index fibre for an optical fibre that have a core of refractive index 1.5 and cladding of index 1.48. also determine the maximum angle for entrance of light if the fibre is put in air Answer the following: --(Any Three) [1SMarks]
- a) Determine :
- i) The critical angle of reflection for core-cladding boundry and ii) The angle of the fiber Given : Refractive index of core=n1=1.4 Refractive index of cladding=n2=1.3
- b) Give a brief account of lasers
- c) A particle is subjected to two parallel SHM’s given by, and sin + and x2=3 — =) in cm. Write the of the resultant SHM
- d) Two parallel simple harmonic motion described by sin(wt+@,) and X2=A2 sin (wt+@,) are superimposed on a Particle. Show that the.amplitude of the resultant SHM is equal to: when the component motions are in phase and
- ii)A1-A2 when they are in Opposite phase, an expression for kinetic energy of a system of a Particle in Centre of Mass CO-ordinate
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